Monday, December 13, 2010

Part E: 3CuCl2(aq)+2Na3PO4(aq)=Cu3(PO4)2(s)+6NACl(aq)

In Part E we took the curpic chloride solution and added sodium phosphate to it. This caused a precipitate (Cu3(PO4)2) to form, as well as aqueous NaCl. The picture shows the precipitate beginning to form. We also filtered the NaCl out of the solid in this step.

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