Monday, December 13, 2010

Part D: CuO(s)+2HCl(aq)=CuCl2(aq)+H2O(aq)

In Part D we added hydrocloric acid (HCl) to the solid cupric oxide. This caused aqueous green cupric chloride (CuCl2) and water to form. The new soultion then drained into the beaker under the filter

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